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AQA 8463 · 4.5.6.1.5 · Velocity–time graphs

Velocity–time graphs: distance is the area

The area mark. Distance travelled is the area under the line, and the mark is for decomposing the shape and summing it — not for any value readable off an axis.

Reviewed family · Studara-authored items · No grade-uplift claim

The lost mark

One answer. Several places the method can fail.

Studara does not reduce the response to right or wrong. The reviewed contract checks these states independently.

Step 1

Gradient

Read the gradient of the line as the acceleration.

Step 2

Decompose the area

Split the region under the line into rectangles and triangles.

Step 3

Sum for distance

Add the areas and state the distance with units.

Why it goes wrong

The diagnosis stays uncertainty-safe.

A wrong response can support a specific measured diagnosis. A blind multiple-choice diagnostic records only a possible cause until later working provides stronger evidence.

01

The error

Reading a value off the vertical axis for distance, instead of computing the area under the line between the two times.

02

Why it survives revision

Gradient-as-acceleration is correct, is taught first, and makes the graph feel fully understood. The confidence from the half that is right is what stops the other half from being questioned.

The worked repair

Repair the smallest broken step.

Teaching is not evidence. This one move is the repair; the proof checks begin after it disappears.

Split the region into rectangles and triangles, compute each area, then add them.

What happens after the repair

Correction is the start, not the result.

Immediate

Asked again straight away, on a different question

The repair leaves the screen and a new authored item checks the method unassisted. Being taught something is never evidence that it was learned, so this is the first stage that counts at all.

Delayed

Asked again after at least 1 day

A parallel form of the same method, unassisted, with the repair no longer on screen. A retest in the same session does not count.

Transfer

Asked again when the surface changes

The transfer form includes a deceleration section or a negative velocity, so area below the axis has to be handled rather than the shape being read as one block.

Exam

Asked again under exam conditions

Timed, carrying the mark tariff, in an exam-like response format and aligned to the specification. Any one of those missing and the evidence is refused.

REVIEWED BOUNDARY

This page covers one reviewed family: 4.5.6.1.5 · Velocity–time graphs. Read gradient as acceleration, decompose changing-speed area into exact regions, and expose the constant-speed shortcut. Other families within the same GCSE Physics topic are outside this reviewed journey, and Studara does not apply the proof label to material that has not been reviewed. No grade-uplift claim is made anywhere on this site.

Straight answers

Before you use this guide.

How do I find distance from a velocity-time graph?

It is the area under the line, not a value read off an axis. Split the shape into rectangles and triangles and add their areas.

What does the gradient represent?

Acceleration. A steeper line is a larger acceleration; a negative gradient is deceleration.

Does Studara guarantee a higher grade?

No. Studara has not run a controlled outcome study and publishes no grade-uplift claim. What has been measured, what is withheld, and the metric that failed its bar are all on the public evidence page.

Turn this method into evidence

Do it once. Then prove it held.

Start this proof journey